33x^2+6x-72=0

Solution for 33x^2+6x-72=0 equation:

33x^2+6x-72=0

a = 33; b = 6; c = -72;
Δ = b2-4ac
Δ = 62-4·33·(-72)
Δ = 9540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9540}=\sqrt{36*265}=\sqrt{36}*\sqrt{265}=6\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{265}}{2*33}=\frac{-6-6\sqrt{265}}{66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{265}}{2*33}=\frac{-6+6\sqrt{265}}{66}
$